How much P2O5 is contained in a 50 pound bag of fertilizer labeled 33-2-11?

How much P2O5 is contained in a 50 pound bag of fertilizer labeled 33-2-11?

• A. 1.5 pounds
• B. 1 pound
• C. 2 pounds
• D. 0.5 pounds

Answer: (B)

To determine how much P2O5 is contained in a 50-pound bag of fertilizer labeled 33-2-11, we need to focus on the middle number in the fertilizer analysis. This number represents the percentage of phosphorus tetroxide (P2O5) in the fertilizer mix. In the case of the 33-2-11 formulation, the middle number is 2, which indicates that the fertilizer contains 2% P2O5. To find out how many pounds of P2O5 are in the 50-pound bag, we can calculate this by multiplying the total weight of the fertilizer by the percentage of P2O5: \[ \text{P2O5} \, \text{(in pounds)} = \text{total weight of fertilizer} \times \left(\frac{\text{percentage of P2O5}}{100}\right) \] Substituting the values: \[ \text{P2O5} = 50 \, \text{pounds} \times \left(\frac{2}{100}\right) = 50 \times 0.02 = 1 \, \text{pound} \] Thus

To determine how much P2O5 is contained in a 50-pound bag of fertilizer labeled 33-2-11, we need to focus on the middle number in the fertilizer analysis. This number represents the percentage of phosphorus tetroxide (P2O5) in the fertilizer mix.

In the case of the 33-2-11 formulation, the middle number is 2, which indicates that the fertilizer contains 2% P2O5. To find out how many pounds of P2O5 are in the 50-pound bag, we can calculate this by multiplying the total weight of the fertilizer by the percentage of P2O5:

[

\text{P2O5} , \text{(in pounds)} = \text{total weight of fertilizer} \times \left(\frac{\text{percentage of P2O5}}{100}\right)

]

Substituting the values:

[

\text{P2O5} = 50 , \text{pounds} \times \left(\frac{2}{100}\right) = 50 \times 0.02 = 1 , \text{pound}

]

Thus